How many combinations are possible for too-punching? 20 10 16 14

The question is asking for the number of possible combinations for a two-punch combination. In combinatorics, a branch of mathematics, the number of possible combinations of n items taken r at a time is given by the formula:<br /><br />C(n, r) = n! / [r!(n-r)!]<br /><br />where "!" denotes factorial, which is the product of all positive integers up to n.<br /><br />In this case, n = 2 (since there are two punches) and r = 2 (since we are looking for combinations of two punches). Plugging these values into the formula, we get:<br /><br />C(2, 2) = 2! / [2!(2-2)!] = 2! / [2!0!] = 2 / [2*1] = 1<br /><br />So, there is only one possible combination for a two-punch combination.<br /><br />Therefore, the correct answer is: 1