Challenge 1 of 5 Score: 0 Start Over 1SO_(2)+3H_(2)Longrightarrow 1H_(2)S+2H_(2)O infty Check 0 2 4 2 1 infty SO_(2) H_(2) H_(2)S H_(2)O SO_(2) H_(2) Reactants Products Leftovers

To determine the products and leftovers in the given chemical reaction, we need to analyze the balanced equation:<br /><br />$1SO_{2} + 3H_{2} \Longrightarrow 1H_{2}S + 2H_{2}O$<br /><br />In this reaction, the reactants are $SO_{2}$ and $H_{2}$, and the products are $H_{2}S$ and $H_{2}O$.<br /><br />The coefficients in the balanced equation indicate the stoichiometric ratios of the reactants and products. In this case, the coefficients are:<br /><br />- $SO_{2}$: 1<br />- $H_{2}$: 3<br />- $H_{2}S$: 1<br />- $H_{2}O$: 2<br /><br />Based on these coefficients, we can determine the following:<br /><br />1. Products: The products of the reaction are $H_{2}S$ and $H_{2}O$.<br />2. Leftovers: Since the coefficients are whole numbers, there are no leftovers in this reaction.<br /><br />Therefore, the correct answer is:<br /><br />Products: $H_{2}S$ and $H_{2}O$<br />Leftovers: None