What is the solution to the equation below? A x=-6 B x=36 C x=6,-6 D x=6 x^2-36=0

To solve the equation $x^{2}-36=0$, we can factor the left side of the equation as a difference of squares:<br /><br />$x^{2}-36 = (x-6)(x+6) = 0$<br /><br />Setting each factor equal to zero gives us the solutions:<br /><br />$x-6 = 0$ or $x+6 = 0$<br /><br />Solving for $x$ in each case, we get:<br /><br />$x = 6$ or $x = -6$<br /><br />Therefore, the correct answer is C) $x=6,-6$.