Find the product . Simplify your answer. d(-d^2+8) square

To find the product \( d(-d^2 + 8) \), we need to distribute \( d \) across the terms inside the parentheses.<br /><br />\[<br />d(-d^2 + 8) = d \cdot (-d^2) + d \cdot 8<br />\]<br /><br />Now, calculate each term separately:<br /><br />1. \( d \cdot (-d^2) = -d^3 \)<br />2. \( d \cdot 8 = 8d \)<br /><br />Combine these results:<br /><br />\[<br />d(-d^2 + 8) = -d^3 + 8d<br />\]<br /><br />So, the simplified answer is:<br /><br />\[<br />\boxed{-d^3 + 8d}<br />\]