Solving a Trigonometric Equation In Exercises 11-16 find all solutions of the equation in the interval [0^circ ,360^circ ) 11. sinx=0

To solve the trigonometric equation $\sin x = 0$ in the interval $[0^{\circ}, 360^{\circ})$, we need to find the values of $x$ for which the sine function is equal to zero.<br /><br />The sine function is equal to zero at the following points within the given interval:<br />- $x = 0^{\circ}$<br />- $x = 180^{\circ}$<br />- $x = 360^{\circ}$<br /><br />Therefore, the solutions to the equation $\sin x = 0$ in the interval $[0^{\circ}, 360^{\circ})$ are:<br />- $x = 0^{\circ}$<br />- $x = 180^{\circ}$<br />- $x = 360^{\circ}$<br /><br />These are the points where the sine function intersects the x-axis within the given interval.