A gas sample has an initial volume of 6.0 L at a pressure of 16 atm. If the pressure is increased to 8.0 atm, what will be the new volume of the gas? Assume temperature remains constant

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature remains constant. Mathematically, this can be expressed as:<br /><br />P1 * V1 = P2 * V2<br /><br />Where:<br />P1 = Initial pressure<br />V1 = Initial volume<br />P2 = Final pressure<br />V2 = Final volume<br /><br />Given information:<br />- Initial volume (V1) = GOLata<br />- Initial pressure (P1) = 1.5 atm<br />- Final pressure (P2) = 8.0 atm<br /><br />We need to find the final volume (V2).<br /><br />Substituting the given values into the equation:<br /><br />1.5 * GOLata = 8.0 * V2<br /><br />Solving for V2:<br /><br />V2 = (1.5 * GOLata) / 8.0<br /><br />Therefore, the new volume of the gas when the pressure is increased to 8.0 atm is (1.5 * GOLata) / 8.0.