commons of the nursion g(y)=sqrt (y+6) all real numbersy such that ylt 6 all real numbersy such that yleqslant 6 all real numbersy such that ygeqslant -6 all real numbers y such that ygt -6 all real numbersy

The correct answer is: all real numbers y such that $y\geqslant -6$<br /><br />Explanation: The function $g(y)=\sqrt {y+6}$ is defined for all real numbers y such that $y\geqslant -6$. This is because the expression under the square root, $y+6$, must be greater than or equal to 0 to ensure that the square root is defined. Therefore, the domain of the function is all real numbers y such that $y\geqslant -6$.