2.T' spulation of Sunny Hills was 108,000 in 1995 and was growing at a rate of 4.5% the population in 2012? Es Eqn __ R co the nearest whole number. Ans: __

To find the population of Sunny Hills in 2012, we can use the formula for exponential growth:<br /><br />\[ P(t) = P_0 \times (1 + r)^t \]<br /><br />where:<br />- \( P(t) \) is the population at time \( t \)<br />- \( P_0 \) is the initial population<br />- \( r \) is the growth rate<br />- \( t \) is the number of years since the initial time<br /><br />Given:<br />- Initial population \( P_0 = 108,000 \)<br />- Growth rate \( r = 4.5\% = 0.045 \)<br />- Time \( t = 2012 - 1995 = 17 \) years<br /><br />Plugging these values into the formula:<br /><br />\[ P(17) = 108,000 \times (1 + 0.045)^{17} \]<br /><br />\[ P(17) = 108,000 \times (1.045)^{17} \]<br /><br />Using a calculator to compute \( (1.045)^{17} \):<br /><br />\[ (1.045)^{17} \approx 2.103 \]<br /><br />Now multiply by the initial population:<br /><br />\[ P(17) = 108,000 \times 2.103 \approx 227,124 \]<br /><br />Rounding to the nearest whole number, the population in 2012 is approximately:<br /><br />\[ \boxed{227,124} \]