Which of these explains why 4^2times 4^6=4^4times 4^4 The base number is 4 The exponents are all even There are 8 fours on each side of the equation. There are 2 terms on each side of the equation.

The question is asking why the equation $4^{2}\times 4^{6}=4^{4}\times 4^{4}$ holds true. To understand this, we need to recall the rule of exponents which states that when multiplying two powers with the same base, we add the exponents. So, $4^{2}\times 4^{6}$ becomes $4^{2+6}$ which simplifies to $4^{8}$. On the other hand, $4^{4}\times 4^{4}$ becomes $4^{4+4}$ which simplifies to $4^{8}$. Therefore, both sides of the equation are equal, which means the equation holds true. The number of fours on each side of the equation is 8, which is why the equation holds true. The base number being 4 and the exponents being even are not relevant to why the equation holds true.