7) A pulley has an efficiency of 85.0% If 475 J are exertedjo lift a 16.0 kg weight, how high is the weight lifted? 85=(wout)/(win)cdot 100

To solve this problem, we need to use the formula for efficiency and the given information to find the height the weight is lifted.<br /><br />Given information:<br />- Efficiency of the pulley: 85.0%<br />- Work input (W_in) = 475 J<br />- Mass of the weight16.0 kg<br /><br />Step 1: Calculate the work output (W_out) using the efficiency formula.<br />Efficiency = (W_out / W_in) × 100<br />85.0% = (W_out / 475 J) × 100<br />W_out = 0.85 × 475 J<br />W_out = 403.75 J<br /><br />Step 2: Calculate the height the weight is lifted using the work-energy principle.<br />Work done = Change in gravitational potential energy<br />W_out = m × g × h<br />403.75 J = 16.0 kg × 9.8 m/s² × h<br />h = 403.75 J / (16.0 kg × 9.8 m/s²)<br />h = 2.5 m<br /><br />Therefore, the weight is lifted 2.5 meters high.