Given a gas is at 14 L and 1 mol, what is the number of moles of the gas when volume changes to 12 L? Round to one decimal place. square mol

## Step 1<br />The problem involves the application of Avogadro's Law, which states that the volume of a gas is directly proportional to the number of moles of the gas, provided the temperature and pressure remain constant. This relationship can be represented by the equation:<br />### \(V1/n1 = V2/n2\)<br />where \(V1\) and \(n1\) are the initial volume and number of moles, and \(V2\) and \(n2\) are the final volume and number of moles.<br /><br />## Step 2<br />In this problem, we are given that the initial volume \(V1\) is 14 L and the initial number of moles \(n1\) is 1 mol. The final volume \(V2\) is 12 L, and we are asked to find the final number of moles \(n2\).<br /><br />## Step 3<br />We can rearrange the equation to solve for \(n2\):<br />### \(n2 = (V2 * n1) / V1\)<br /><br />## Step 4<br />Substitute the given values into the equation:<br />### \(n2 = (12 L * 1 mol) / 14 L = 0.8571 mol\)<br /><br />## Step 5<br />The problem asks us to round the answer to one decimal place, so the final answer is 0.9 mol.