Because the mean is very sensitive to extreme values, It is not a resestant measure of center. By deleting some low values and high values the throed mean is more resistant. To find the 10% thromed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the trip 10% of the values, then calculate the mean of 20% thimed mean. the remaining values. Use be avial loads (pounds)of alumbum cans listed below for cans that are 00111 in thick Idently any outions, then compare the moder, moun 10% 248261268273275279282283284284 287283289-292293296296299310504 Identily any outiors. Select the correct choice below and, I necessary, fill in the answer box to complete your choice A. The outier(s) islare square pounds (Type a whole number Use a comma to sopurate answers as needed) B. There are no outsers

To find the 10% trimmed mean for the given data set, we first need to arrange the data in ascending order:<br /><br />$248, 261, 268, 273, 275, 279, 282, 283, 284, 284, 284, 287, 283, 289, 292, 293, 296, 296, 299, 310, 504$<br /><br />Next, we need to delete the bottom 10% of the values and the top 10% of the values. Since there are 21 values in the data set, the bottom 10% corresponds to the 2nd value and the top 10% corresponds to the 20th value.<br /><br />After deleting these values, we are left with the following 18 values:<br /><br />$261, 268, 273, 275, 279, 282, 283, 284, 284, 284, 287, 283, 289, 292, 293, 296, 296, 310$<br /><br />Now, we can calculate the mean of these 18 values:<br /><br />$\text{Mean} = \frac{261 + 268 + 273 + 275 + 279 + 282 + 283 + 284 + 284 + 284 + 287 + 283 + 289 + 292 + 293 + 296 + 296 + 310}{18} = 284.94$<br /><br />Therefore, the 10% trimmed mean for the given data set is 284.94 pounds.<br /><br />Answer: B. There are no outliers.