What is the magnitude of the electrostatic force between a charge of +3.0times 10^-5C and a charge of +6.0times 10^-6C separated by 0.30 me 1.8times 10^1N or 18 N 5.4times 10^-2N or .054 N 1.8times 10^-3N or.0018 N 5.4times 10^0N or 5.4 N Multiple Choice 1 point

To find the magnitude of the electrostatic force between two charges, we can use Coulomb's law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.<br /><br />The formula for Coulomb's law is:<br /><br />F = k * (q1 * q2) / r^2<br /><br />Where:<br />F is the magnitude of the electrostatic force,<br />k is the Coulomb constant (approximately 8.99 x 10^9 N m^2/C^2),<br />q1 and q2 are the charges,<br />r is the distance between the charges.<br /><br />Given information:<br />Charge 1 (q1) = +3.0 x 10^-5 C<br />Charge 2 (q2) = +6.0 x 10^-6 C<br />Distance (r) = 0.30 m<br /><br />Substituting the values into the formula:<br /><br />F = (8.99 x 10^9 N m^2/C^2) * ((3.0 x 10^-5 C) * (6.0 x 10^-6 C)) / (0.30 m)^2<br />F = (8.99 x 10^9 N m^2/C^2) * (1.8 x 10^-11 C^2) / (0.09 m^2)<br />F = 1.8 x 10^1 N or 18 N<br /><br />Therefore, the correct answer is:<br />$1.8\times 10^{1}N$ or 18 N