In the exponential equation y=2(3)^wedge x what is the starting value? 2 3

The starting value of the exponential equation $y=2(3)^x$ is the value of $y$ when $x=0$. To find this, we can substitute $x=0$ into the equation:<br /><br />$y=2(3)^0$<br /><br />Since any number raised to the power of 0 is 1, we have:<br /><br />$y=2(1)$<br /><br />Therefore, the starting value of the exponential equation $y=2(3)^x$ is 2.