What is the percent of Nitrogen in N_(2)O_(7) ? The molar mass for N_(2)O_(7) is 140.02g/mol 20% 55% 100% 30%

To find the percent of nitrogen in $N_{2}O_{7}$, we need to calculate the molar nitrogen and oxygen separately, and then determine the proportion of nitrogen in the compound.<br /><br />Step 1: Calculate the molar mass of nitrogen.<br />The molar mass of nitrogen (N) is 14.01 g/mol.<br /><br />Step 2: Calculate the molar mass of oxygen.<br />The molar mass of oxygen (O) is 16.00 g/mol.<br /><br />Step 3: Calculate the molar mass of $N_{27}$.<br />The molar mass of $N_{2}O_{7}$ is given as 140.02 g/mol.<br /><br />Step 4: Calculate the total mass of nitrogen in $N_{2}O_{7}$.<br />Since there are two nitrogen atoms in $N_{2}O_{7}$, the total mass of nitrogen is 2 * 14.01 g 28.02 g/mol.<br /><br />Step 5: Calculate the percent of nitrogen in $N_{2}O_{7}$.<br />Percent of nitrogen = (Total mass of nitrogen / Molar mass of $N_{2}O_{7}$) *<br />Percent of nitrogen = (28.02 g/mol / 140.02 g/mol) * 100<br />Percent of nitrogen ≈ Therefore, the percent of nitrogen in $N_{2}O_{7}$ is approximately 20%.