A sorted list of numbers contains 200 elements. Which of the following is closest to the maximum number of list elements that will need to be examined when performing a binary search for a particular value in the list? A square B ) 8 C 100 D square

To determine the maximum number of elements that need to be examined when performing a binary search on a sorted list of 200 elements, we can use the concept of the binary search algorithm.<br /><br />In a binary search, the algorithm divides the search space in half with each iteration. The maximum number of elements that need to be examined is determined by the number of times the search space can be divided in half until the target value is found or the search space is empty.<br /><br />In this case, the search space starts at 200 elements and is divided in half with each iteration. The number of iterations required to reduce the search space to 1 element is given by the logarithm base 2 of 200.<br /><br />$\log_2(200) \approx 7.64$<br /><br />Since the number of iterations must be an integer, we round up to the nearest whole number, which is 8.<br /><br />Therefore, the maximum number of elements that need to be examined when performing a binary search for a particular value in the list is 8.<br /><br />The correct answer is B) 8.