10. Given the balanced equation of NaOH(s)+CO2(g)arrow NaHCO3 how many liters of Carbon Dioxide are needed to produce 2.00times 102g of NaHCO3 of at standard temperature and pressure? 2.38 L 9.41 L 53.3 L 84.0 L

To solve this problem, we need to use the balanced chemical equation and the given information to determine the amount of carbon dioxide (CO2) required to produce a certain amount of sodium bicarbonate (NaHCO3).<br /><br />:<br />- Balanced chemical equation: NaOH(s) + CO2(g) → NaHCO3(s)<br />- Mass of NaHCO3 produced: 2.00 × 10^2 g<br /><br />Step 1: Calculate the molar mass of NaHCO3.<br />Molar mass of NaHCO3 = 23.0 (Na) + 1.0 (H) + 12 (C) + 3×16.0 (O) = 84.0 g/mol<br /><br />Step 2: Calculate the number of moles of NaHCO3 produced.<br />Number of moles of NaHCO3 = Mass of NaHCO3 / Molar mass of NaHCO3<br />Number of moles of NaHCO3 = 2.00 × 10^2 g84.0 g/mol = 2.38 mol<br /><br />Step 3: Use the balanced chemical equation to determine the number of moles of CO2 required.<br />According to the balanced equation, 1 mole of NaHCO3 is produced from 1 mole of CO2.<br />Number of moles of CO2 required = Number of moles of NaHCO3 = 2.38 mol<br /><br />Step 4: Calculate the volume of CO2 required at standard temperature and pressure (STP).<br />At STP, 1 mole of any gas occupies 22.4 liters.<br />Volume of CO2 required = Number of moles of CO2 × 22.4 L/mol<br />Volume of CO2 required = 2.38 mol × 22.4 L/mol = 53.3 L<br /><br />Therefore, the correct answer is 53.3 L.