A given mass of air has a volume of 6.00 Lat 353K At constant pressure the temperature is decreased to 313K. Calculate the final volume for the ga: 5.32 L 3.00 L 12.0 L 6.77 L

## Step 1<br />The problem involves the application of Charles's Law, which states that the volume of a given amount of gas is directly proportional to its temperature on an absolute scale, provided the pressure is kept constant. This relationship can be mathematically represented as:<br />### \( \frac{V1}{T1} = \frac{V2}{T2} \)<br />where \( V1 \) and1 \) are the initial volume and temperature, and \( V2 \) and \( T2 \) are the final volume and temperature.<br /><br />## Step 2<br />In this problem, the initial volume \( V1 \) is 6.00 L, the initial temperature \( T1 \) is 353 K, and the final temperature \( T2 \) is 313 K. We are asked to find the final volume \( V2 \).<br /><br />## Step 3<br />We can rearrange the Charles's Law formula to solve for \( V2 \):<br />### \( V2 = V1 \times \frac{T2}{T1} \)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \( V2 = 6.00 \, L \times \frac{313 \, K}{353 \, K} \)<br /><br />## Step 5<br />Calculate the value of \( V2 \).