Let A=[} -1&-4 0&-7 3&5 ] Find -4A -4A=square

To find \(-4A\), we need to multiply each element of matrix \(A\) by \(-4\).<br /><br />Given:<br />\[ A = \begin{pmatrix} -1 & -4 \\ 0 & -7 \\ 3 & 5 \end{pmatrix} \]<br /><br />We multiply each element of \(A\) by \(-4\):<br /><br />\[<br />-4A = -4 \times \begin{pmatrix} -1 & -4 \\ 0 & -7 \\ 3 & 5 \end{pmatrix} = \begin{pmatrix} -4 \times -1 & -4 \times -4 \\ -4 \times 0 & -4 \times -7 \\ -4 \times 3 & -4 \times 5 \end{pmatrix}<br />\]<br /><br />Calculating each element:<br /><br />\[<br />-4A = \begin{pmatrix} 4 & 16 \\ 0 & 28 \\ -12 & -20 \end{pmatrix}<br />\]<br /><br />So, the result is:<br /><br />\[<br />-4A = \begin{pmatrix} 4 & 16 \\ 0 & 28 \\ -12 & -20 \end{pmatrix}<br />\]