Use the quadratic formula to solve for x. 4x^2-x=4 Round your answer to the nearest hundredth. If there is more than one solution, separate them with commas. x=

Rearrange the equation:<br />$4x^2 - x - 4 = 0$<br />Determine the coefficients $a, b, c$:<br />$a = 4, b = -1, c = -4$<br />Find the discriminant:<br />$\Delta = b^2 - 4ac = {(-1)}^{2} - 4 \times 4 \times (-4) = 1 + 64 = 65$<br />Find the roots of the quadratic equation:<br />$\displaystyle \begin{align}&x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}\\&=\frac{-(-1) \pm \sqrt{{{(-1)}^{2}-4 \times 4 \times (-4)}}}{2 \times 4}\\&=\frac{1 \pm \sqrt{65}}{8}\end{align}$<br />Calculate:<br />$\displaystyle x_1 = \frac{1 + \sqrt{65}}{8} \approx 1.28, x_2 = \frac{1 - \sqrt{65}}{8} \approx -0.78$<br />Therefore, the solutions are:<br />$x = 1.28, -0.78$