2KClO_(3)arrow 2KCl+3O_(2) If there are 6.73times 10^23 particles of KClO_(3) find the number of grams of O_(2) that are produced. (mmO_(2)=32g/mol)(mmKClO_(3)=122g/mol) 53.668 107.32 g 82.73 g 42.10 g

To solve this problem, we need to follow these steps:<br /><br />1. Calculate the number of moles of KClO3 using Avogadro's number.<br />2. Use the stoichiometry of the balanced chemical equation to find the number of moles of O2 produced.<br />3. Convert the number of moles of O2 to grams using the molar mass of O2.<br /><br />Given information:<br />- Balanced chemical equation: 2KClO3 → 2KCl + 3O2<br />- Number of particles of KClO3: 6.73 × 10^23<br />- Molar mass of O2: 32 g/mol<br />- Molar mass of KClO3: 122 g/mol<br /><br />Step 1: Calculate the number of moles of KClO3.<br />Number of moles of KClO3 = Number of particles / Avogadro's number<br />Number of moles of KClO3 = 6.73 × 10^23 / 6.022 × 10^23<br />Number of moles of KClO3 = 1.12 moles<br /><br />Step 2: Use the stoichiometry of the balanced chemical equation to find the number of moles of O2 produced.<br />According to the balanced chemical equation, 2 moles of KClO3 produce 3 moles of O2.<br />Number of moles of O2 produced = (3/2) × Number of moles of KClO3<br />Number of moles of O2 produced = (3/2) × 1.12 moles<br />Number of moles of O2 produced = 1.68 moles<br /><br />Step 3: Convert the number of moles of O2 to grams using the molar mass of O2.<br />Mass of O2 = Number of moles of O2 × Molar mass of O2<br />Mass of O2 = 1.68 moles × 32 g/mol<br />Mass of O2 = 53.76 g<br /><br />Therefore, the correct answer is 53.76 g.