6. Derise has 90 in a savings account that compounded amaly to the tearest pering how much will she have in 3 years? don't answer, or slip ing spaces in answer. square

To solve this problem, we need to use the formula for compound interest:<br /><br />\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \]<br /><br />where:<br />- \( A \) is the amount of money accumulated after \( n \) years, including interest.<br />- \( P \) is the principal amount (the initial amount of money).<br />- \( r \) is the annual interest rate (in decimal).<br />- \( n \) is the number of times that interest is compounded per year.<br />- \( t \) is the time the money is invested for, in years.<br /><br />Given:<br />- \( P = 90 \)<br />- \( r = 0.05 \) (assuming an annual interest rate of 5%)<br />- \( n = 1 \) (compounded annually)<br />- \( t = 3 \)<br /><br />Plugging these values into the formula:<br /><br />\[ A = 90 \left(1 + \frac{0.05}{1}\right)^{1 \cdot 3} \]<br />\[ A = 90 \left(1 + 0.05\right)^3 \]<br />\[ A = 90 \left(1.05\right)^3 \]<br />\[ A = 90 \times 1.157625 \]<br />\[ A = 103.915625 \]<br /><br />Rounding to the nearest cent, Derise will have approximately 103.92 in her savings account after 3 years.