Quadratic Formula , Perfe atic formula. #2. x^2+3x-4=0

To solve the quadratic equation $x^{2}+3x-4=0$, we can use the quadratic formula:<br /><br />$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$<br /><br />where $a$, $b$, and $c$ are the coefficients of the quadratic equation.<br /><br />In this case, $a = 1$, $b = 3$, and $c = -4$.<br /><br />Plugging these values into the quadratic formula, we get:<br /><br />$x = \frac{-3 \pm \sqrt{2 - 4(1)(-4)}}{2(1)}$<br /><br />$x = \frac{-3 \pm \sqrt{9 + 16}}{2}$<br /><br />$x = \frac{-3 \pm \sqrt{25}}{2}$<br /><br />$x = \frac{-3 \pm 5}{2}$<br /><br />So, the solutions to the quadratic equation $x^{2}+3x-4=0$ are:<br /><br />$x_1 = \frac{-3 + 5}{2$<br /><br />$x_2 = \frac{-3 - 5}{2} = -4$<br /><br />Therefore, the solutions to the quadratic equation $x^{2}+3x-4=0$ are $x = 1$ and $x = -4$.