9.Write in logarithmic form. 4^-3=(1)/(64) __

The given equation is $4^{-3}=\frac {1}{64}$. This is an exponential equation where the base is 4, the exponent is -3, and the result is $\frac {1}{64}$. We need to convert this into logarithmic form. <br /><br />In logarithmic form, the equation is written as $\log _ { b } x = y$, where $b$ is the base, $x$ is the result, and $y$ is the exponent. <br /><br />So, in this case, the base $b$ is 4, the result $x$ is $\frac {1}{64}$, and the exponent $y$ is -3. <br /><br />Therefore, the logarithmic form of the given equation is $\log _ { 4 } \frac {1}{64} = -3$.