What is printed by the following program? let isRaining=false let isCloudy=false: atisSunny=lisRainingdacute (e)lisCloudy) let isSummerequiv false: let isWarmequiv isSunnyVert isSummer! console.log(''ILit warm:''+isWarm) Ia it worm true Ia it worm folse Ia it worm yes Is it warmino

The program you provided contains several syntax errors and logical inconsistencies. Let's go through the code step by step to understand what it should do and identify any mistakes:<br /><br />```javascript<br />let isRaining = false;<br />let isCloudy = false;<br />let isSunny = isRaining &&!isCloudy; // This line has a syntax error<br />let isSummer = false;<br />let isWarm = isSunny || isSummer; // This line has a syntax error<br />console.log('It is warm: ' isWarm);<br />```<br /><br />1. `let isRaining = false;` - This initializes `isRaining` to `false`.<br />2. `let isCloudy = false;` - This initializes `isCloudy` to `false`.<br />3. `let isSunny = isRinging &&!isCloudy;` - This line has a syntax error. It should be `let isSunny = isRaining &&!isCloudy;`. This line checks if it is sunny by ensuring it is not raining and not cloudy.<br />4. `let isSummer = false;` - This initializes `isSummer` to `false`.<br />5. `let isWarm = isSunny || isSummer;` - This line has a syntax error. It should be `let isWarm = isSunny || isSummer;`. This line checks if it is warm by checking if it is sunny or summer.<br />6. `console.log('It is warm: ' isWarm);` - This line logs the message 'It is warm: 'ollowed by the value of `isWarm`.<br /><br />Given the corrected code, let's analyze the logical conditions:<br /><br />- `isRaining` is `false`.<br />- `isCloudy` is `false`.<br />- `isSunny` is `false` because `isRaining` is `false` and `!isCloudy` is `true`, but the result of `false && true` is `false`.<br />- `isSummer` is `false`.<br />- `isWarm` is `false` because `isSunny` is `false` and `isSummer` is `false`, and the result of `false || false` is `false`.<br /><br />Therefore, the output of the program will be:<br /><br />```<br />It is warm: false<br />```<br /><br />So, the correct answer is:<br />```<br />It is warm: false<br />```