Solve f(x)=g(x) What are the points of intersection of the graphs of the two functions? f(x)=4(x^2-3); g(x)=4x^2+3x+12 If f(x)=g(x) then x=-8 (Simplify your answer. Use a comma to soparato answers as nooded.) The point(s) of intesection of the two graphs is/aro square (Simplify your answer. Type an ordered pair. Uso a cofnma to soparato answers as nooded.)

To find the points of intersection of the graphs of the two functions, we need to solve the equation $f(x) = g(x)$.<br /><br />Given:<br />$f(x) = 4(x^2 - 3)$<br />$g(x) = 4x^2 + 3x + 12$<br /><br />Setting $f(x) = g(x)$, we have:<br />$4(x^2 - 3) = 4x^2 + 3x + 12$<br /><br />Expanding and simplifying the equation:<br />$4x^2 - 12 = 4x^2 + 3x + 12$<br />$-12 = 3x + 12$<br />$-24 = 3x$<br />$x = -8$<br /><br />So, the value of $x$ at the point of intersection is $x = -8$.<br /><br />To find the corresponding $y$-coordinate, we can substitute $x = -8$ into either $f(x)$ or $g(x)$.<br /><br />Using $f(x)$:<br />$f(-8) = 4((-8)^2 - 3) = 4(64 - 3) = 4(61) = 244$<br /><br />Therefore, the point of intersection of the two graphs is $(-8, 244)$.