2. Calculate the number of moles in 16.7 g of Al_(2)(SO_(4))_(3) 3. Calculate the mass in grams of 2.50 mol Al_(2)(SO_(4))_(3)

2. To calculate the number of moles in 16.7 g of $Al_{2}(SO_{4})_{3}$, we need to use the formula:<br /><br />Moles = Mass / Molar Mass<br /><br />First, let's calculate the molar mass of $Al_{2}(SO_{4})_{3}$:<br /><br />Molar Mass of $Al_{2}(SO_{4})_{3}$ = (2 * Atomic Mass of Al) + (3 * Atomic Mass of S) + (12 * Atomic Mass of O)<br />Molar Mass of $Al_{2}(SO_{4})_{3}$ = (2 * 26.98 g/mol) + (3 * 32.07 g/mol) + (12 * 16.00 g/mol)<br />Molar Mass of $Al_{2}(SO_{4})_{3}$ = 53.96 g/mol + 96.21 g/mol + 192.00 g/mol<br />Molar Mass of $Al_{2}(SO_{4})_{3}$ = 342.17 g/mol<br /><br />Now, we can calculate the number of moles:<br /><br />Moles = 16.7 g / 342.17 g/mol<br />Moles ≈ 0.0486 mol<br /><br />Therefore, there are approximately 0.0486 moles in 16.7 g of $Al_{2}(SO_{4})_{3}$.<br /><br />3. To calculate the mass in grams of 2.50 mol $Al_{2}(SO_{4})_{3}$, we can use the formula:<br /><br />Mass = Moles * Molar Mass<br /><br />We already calculated the molar mass of $Al_{2}(SO_{4})_{3}$ in the previous question, which is 342.17 g/mol.<br /><br />Now, we can calculate the mass:<br /><br />Mass = 2.50 mol * 342.17 g/mol<br />Mass = 855.43 g<br /><br />Therefore, the mass of 2.50 mol $Al_{2}(SO_{4})_{3}$ is 855.43 g.