Find the product Simplify your answer. -n^2(n^2+8) square

To find the product and simplify the expression \(-n^{2}(n^{2}+8)\), we need to distribute \(-n^{2}\) to each term inside the parentheses.<br /><br />\[<br />-n^{2}(n^{2} + 8)<br />\]<br /><br />First, distribute \(-n^{2}\) to \(n^{2}\):<br /><br />\[<br />-n^{2} \cdot n^{2} = -n^{4}<br />\]<br /><br />Next, distribute \(-n^{2}\) to \(8\):<br /><br />\[<br />-n^{2} \cdot 8 = -8n^{2}<br />\]<br /><br />Now, combine these results:<br /><br />\[<br />-n^{4} - 8n^{2}<br />\]<br /><br />So, the simplified form of the expression is:<br /><br />\[<br />\boxed{-n^{4} - 8n^{2}}<br />\]