Question 3 (20 points) What are the coefficients for this equation to be properly balanced? underline ( )N_(2)+underline ( )F_(2)arrow underline ( )NF_(3) 1,3,2 b 2,1,2 C 2,1,1 d 1,2,2

## Step 1<br />The given equation is \(N_{2} + F_{2} \rightarrow NF_{3}\). This equation represents a chemical reaction where nitrogen (N2) and fluorine (F2) combine to form nitrogen trifluoride (NF3).<br /><br />## Step 2<br />To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. This is in line with the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.<br /><br />## Step 3<br />Looking at the equation, we can see that there are 2 nitrogen atoms on the left side (in \(N_{2}\)) and 1 nitrogen atom on the right side (in \(NF_{3}\)). Similarly, there are 2 fluorine atoms on the left side (in \(F_{2}\)) and 3 fluorine atoms on the right side (in \(NF_{3}\)).<br /><br />## Step 4<br />To balance the nitrogen atoms, we need to multiply \(NF_{3}\) by 2, giving us 2 nitrogen atoms on both sides. This changes the equation to \(N_{2} + F_{2} \rightarrow 2NF_{3}\).<br /><br />## Step 5<br />Now, we have 2 nitrogen atoms on both sides, but we have 6 fluorine atoms on the right side (in \(2NF_{3}\)) and only 2 fluorine atoms on the left side (in \(F_{2}\)). To balance the fluorine atoms, we need to multiply \(F_{2}\) by 3, giving us 6 fluorine atoms on both sides. This changes the equation to \(N_{2} + 3F_{2} \rightarrow 2NF_{3}\).<br /><br />## Step 6<br />Now, the equation is balanced with 2 nitrogen atoms and 6 fluorine atoms on both sides. Therefore, the coefficients for the equation to be properly balanced are 1, 3, and 2.