Solve the equation ln(6x+6)=1 The exact solution (using exponents) is z = x=square The solution, rounded to 4 decimal places is z= x=square

To solve the equation $ln(6x+6)=1$, we can use the property of logarithms that states $ln(a)=b$ is equivalent to $e^b=a$.<br /><br />So, we can rewrite the equation as $e^1=6x+6$.<br /><br />Simplifying, we get $e=6x+6$.<br /><br />Subtracting 6 from both sides, we get $e-6=6x$.<br /><br />Dividing both sides by 6, we get $x=\frac{e-6}{6}$.<br /><br />Therefore, the exact solution is $x=\frac{e-6}{6}$.<br /><br />To find the solution rounded to 4 decimal places, we can substitute the value of $e$ (approximately 2.71828) into the equation.<br /><br />$x=\frac{2.71828-6}{6}\approx-0.5854$<br /><br />Therefore, the solution rounded to 4 decimal places is $x=-0.5854$.