Find the product.. Simplify your answer. 2(2v^2-2v+1) square

To find the product and simplify the expression \(2(2v^2 - 2v + 1)\), we need to distribute the 2 to each term inside the parentheses.<br /><br />Let's break it down step by step:<br /><br />1. Distribute the 2 to the first term:<br /> \[<br /> 2 \cdot 2v^2 = 4v^2<br /> \]<br /><br />2. Distribute the 2 to the second term:<br /> \[<br /> 2 \cdot (-2v) = -4v<br /> \]<br /><br />3. Distribute the 2 to the third term:<br /> \[<br /> 2 \cdot 1 = 2<br /> \]<br /><br />Now, combine all these results:<br />\[<br />4v^2 - 4v + 2<br />\]<br /><br />So, the simplified form of the expression \(2(2v^2 - 2v + 1)\) is:<br />\[<br />\boxed{4v^2 - 4v + 2}<br />\]