Find the domain of the function. f(s)=(sqrt (s-2))/(s-4) all real numbers such that sgeqslant 4 all real numbers a such that sleqslant 4 all real numbers except s=2 and 6=4 all real numbers such that 6leqslant 4 except s=2 all real numbers a such that sgeqslant 2 except s=4

To find the domain of the function $f(s)=\frac {\sqrt {s-2}}{s-4}$, we need to consider the restrictions on the variable $s$.<br /><br />The square root function $\sqrt{s-2}$ is defined for all real numbers $s$ such that $s-2 \geq 0$, which means $s \geq 2$.<br /><br />The denominator $s-4$ cannot be equal to zero, as division by zero is undefined. Therefore, $s \neq 4$.<br /><br />Combining these two conditions, the domain of the function $f(s)$ is all real numbers $s$ such that $s \geq 2$ except $s=4$.<br /><br />Therefore, the correct answer is: all real numbers such that $s\geqslant 2$ except $s=4$.