What is the probability of tossing 21 or more heads or more out of 30 tosses? Answer to 2 decimal places as a percent.Ex: if your answer is 4.545% answer 4.55

To solve this problem, we can use the binomial probability formula. The binomial probability formula is given by:<br /><br />P(X = k) = (n choose k) * p^k * (1-p)^(n-k)<br /><br />where n is the number of trials, k is the number of successes, and p is the probability of success.<br /><br />In this case, we want to find the probability of getting 21 or more heads out of 30 tosses. So, we need to calculate the probability of getting 21, 22, 23,..., up to 30 heads.<br /><br />Let's calculate the probability of getting 21 heads:<br /><br />P(X = 21) = (30 choose 21) * (1/2)^21 * (1/2)^9<br /> = 30! / (21! * 9!) * (1/2)^30<br /> = 0.055<br /><br />Now, we need to calculate the probabilities for 22, 23,..., up to 30 heads and add them together.<br /><br />P(X >= 21) = P(X = 21) + P(X = 22) + P(X = 23) +... + P(X = 30)<br /><br />Calculating each term individually and adding them up, we get:<br /><br />P(X >= 21) ≈ 0.055 + 0.028 + 0.011 + 0.004 + 0.001 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 + 0.000 +