Given the following balanced equation, how much of potassium chloride (KCl) can theoretically be produced if 48.5 grams of KClO_(3) used? 2KClO_(3)arrow 2KCl+3O_(2) Multiple Choice 1 point

To determine how much potassium chloride (KCl) can be produced from 48.5 grams of KClO3, we need to follow these steps:<br /><br />1. Calculate the molar mass of KClO3.<br />2. Convert the given mass of KClO3 to moles.<br />3. Use the stoichiometry of the balanced equation to find the moles of KCl produced.<br />4. Convert the moles of KCl to grams.<br /><br />Let's go through each step:<br /><br />1. Molar mass of KClO3:<br /> - Potassium (K): 39.10 g/mol<br /> - Chlorine (Cl): 35.45 g/mol<br /> - Oxygen (O): 16.00 g/mol<br /> - Molar mass of KClO3 = 39.10 + 35.45 + (3 × 16.00) = 122.55 g/mol<br /><br />2. Convert the given mass of KClO3 to moles:<br /> - Moles of KClO3 = 48.5 g / 122.55 g/mol = 0.396 moles<br /><br />3. Use the stoichiometry of the balanced equation to find the moles of KCl produced:<br /> - According to the balanced equation, 2 moles of KClO3 produce 2 moles of KCl.<br /> - Therefore, 0.396 moles of KClO3 will produce 0.396 moles of KCl.<br /><br />4. Convert the moles of KCl to grams:<br /> - Molar mass of KCl = 39.10 g/mol (K) + 35.45 g/mol (Cl) = 74.55 g/mol<br /> - Mass of KCl = 0.396 moles × 74.55 g/mol = 29.6 grams<br /><br />Therefore, the theoretical yield of potassium chloride (KCl) that can be produced from. of KClO3 is 29.6 grams.