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11. How many molecules are contained in each compound? a. 1.35 mol of carbon disulfide (CS_(2)) b. 0.254 mol of diarsenic trioxide (As_(2)O_(3)) c. 1.25 mol of water d. 150.0 mol of HCl

Problemas

11. How many molecules are contained in each compound?
a. 1.35 mol of carbon disulfide (CS_(2))
b. 0.254 mol of diarsenic trioxide (As_(2)O_(3))
c. 1.25 mol of water
d. 150.0 mol of HCl

11. How many molecules are contained in each compound? a. 1.35 mol of carbon disulfide (CS_(2)) b. 0.254 mol of diarsenic trioxide (As_(2)O_(3)) c. 1.25 mol of water d. 150.0 mol of HCl

Solución

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Ricardoexperto · Tutor durante 3 años
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To determine the number of molecules in each compound, we need to use Avogadro's number, which is \(6.022 \times 10^{23}\) molecules per mole.<br /><br />a. For 1.35 mol of carbon disulfide (CS₂):<br />\[ \text{Number of molecules} = 1.35 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \]<br />\[ \text{Number of molecules} = 8.1297 \times 10^{23} \, \text{molecules} \]<br /><br />b. For 0.254 mol of diarsenic trioxide (As₂O₃):<br />\[ \text{Number of molecules} = 0.254 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \]<br />\[ \text{Number of molecules} = 1.532 \times 10^{23} \, \text{molecules} \]<br /><br />c. For 1.25 mol of water (H₂O):<br />\[ \text{Number of molecules} = 1.25 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \]<br />\[ \text{Number of molecules} = 7.5275 \times 10^{23} \, \text{molecules} \]<br /><br />d. For 150.0 mol of HCl:<br />\[ \text{Number of molecules} = 150.0 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \]<br />\[ \text{Number of molecules} = 9.033 \times 10^{25} \, \text{molecules} \]<br /><br />So, the number of molecules in each compound is:<br />a. \(8.1297 \times 10^{23}\) molecules of CS₂<br />b. \(1.532 \times 10^{23}\) molecules of As₂O₃<br />c. \(7.5275 \times 10^{23}\) molecules of H₂O<br />d. \(9.033 \times 10^{25}\) molecules of HCl
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