What is the magnitude of the impulse of a wall on a 0.5 kg ball that strikes horizontally at 25m/s and rebounds horizontally at 25 mis? POSSIBLE POINTS: 0.25 100kgcdot m/s 25kgcdot m/s 50kgcdot m/s 80kgcdot m/s 12.5kgcdot m/s

## Step 1: <br />The impulse experienced by an object is equal to the change in momentum of the object. The momentum of an object is given by the product of its mass and velocity. <br /><br />### \( Impulse = Change\ in\ Momentum \)<br /><br />## Step 2:<br />The initial momentum of the ball is given by the product of its mass and initial velocity. <br /><br />### \( Initial\ Momentum = Mass \times Initial\ Velocity \)<br /><br />## Step 3:<br />The final momentum of the ball is given by the product of its mass and final velocity. <br /><br />### \( Final\ Momentum = Mass \times Final\ Velocity \)<br /><br />## Step 4:<br />The change in momentum is the difference between the final and initial momentum. <br /><br />### \( Change\ in\ Momentum = Final\ Momentum - Initial\ Momentum \)<br /><br />## Step 5:<br />Substitute the given values into the formula to calculate the change in momentum. <br /><br />### \( Change\ in\ Momentum = (0.5 kg \times 25 m/s) - (0.5 kg \times -25 m/s) \)