Solve 2t^2-16t+24=0 by factoring . Enter your answers below t=square t=square

To solve the quadratic equation $2t^{2}-16t+24=0$ by factoring, we first factor out the common factor of 2 from each term:<br /><br />$2(t^{2}-8t+12)=0$<br /><br />Next, we factor the quadratic expression inside the parentheses:<br /><br />$2(t-6)(t-2)=0$<br /><br />Now, we set each factor equal to zero and solve for $t$:<br /><br />$t-6=0$ or $t-2=0$<br /><br />$t=6$ or $t=2$<br /><br />Therefore, the solutions to the equation $2t^{2}-16t+24=0$ are $t=6$ and $t=2$.