To stop a 2,9 kg ball going 2.2m/s requires 7.6 N over 4.4 seconds to stop What was the momentum of t Round to 1 decimal place. square

To find the momentum of the ball, we need to use the formula for momentum:<br /><br />\[ \text{momentum} = \text{mass} \times \text{velocity} \]<br /><br />Given:<br />- Mass of the ball, \( m = 2.9 \, \text{kg} \)<br />- Velocity of the ball, \( v = 2.2 \, \text{m/s} \)<br /><br />Substitute the given values into the formula:<br /><br />\[ \text{momentum} = 2.9 \, \text{kg} \times 2.2 \, \text{m/s} \]<br /><br />Calculate the momentum:<br /><br />\[ \text{momentum} = 6.38 \, \text{kg} \cdot \text{m/s} \]<br /><br />Therefore, the momentum of the ball is \( 6.4 \, \text{kg} \cdot \text{m/s} \) (rounded to 1 decimal place).