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Graham's Law states that the rate of diffusion for a gas is: Independent of the gas's mass. Proportional to the gas's density. Dependent on the temperature alone. Inversely proportional to the square root of the gas's molar mass.

Problemas

Graham's Law states that the rate of diffusion for a gas is:
Independent of the gas's mass.
Proportional to the gas's density.
Dependent on the temperature alone.
Inversely proportional to the square root of the gas's molar mass.

Graham's Law states that the rate of diffusion for a gas is: Independent of the gas's mass. Proportional to the gas's density. Dependent on the temperature alone. Inversely proportional to the square root of the gas's molar mass.

Solución

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Alejandromaestro · Tutor durante 5 años
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The correct answer is:<br /><br />**Inversely proportional to the square root of the gas's molar mass.**<br /><br />### Explanation:<br />Graham's Law of Diffusion (or Effusion) states that the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, it can be expressed as:<br /><br />\[<br />\frac{\text{Rate}_1}{\text{Rate}_2} = \sqrt{\frac{M_2}{M_1}}<br />\]<br /><br />Where:<br />- \( \text{Rate}_1 \) and \( \text{Rate}_2 \) are the rates of diffusion or effusion for two gases.<br />- \( M_1 \) and \( M_2 \) are the molar masses of the two gases.<br /><br />This means that lighter gases (with smaller molar masses) diffuse or effuse faster than heavier gases (with larger molar masses).
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