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a brident finds that the muss of a chamcol sample is tident is meatend to report at muscrements in proper S I the student must convert the music to kilograms. What is echamical sample in kilograms? ((337mg)/(1))times ((1g)/(1000mg))times ((1kg)/(1000g)) e ((337mg)/(1))times ((1000mg)/(1g))times ((1g)/(1000kg)) e ((337mg)/(1))times ((1g)/(1000mg))times ((1000g)/(1kg)) e ((337mg)/(1))times ((1000g)/(1mg))times ((1000kg)/(1g))

Problemas

a brident finds that the muss of a chamcol sample is
tident is meatend to report at muscrements in proper S
I the student must convert the music to kilograms. What is
echamical sample in kilograms?
((337mg)/(1))times ((1g)/(1000mg))times ((1kg)/(1000g))	e
((337mg)/(1))times ((1000mg)/(1g))times ((1g)/(1000kg))	e
((337mg)/(1))times ((1g)/(1000mg))times ((1000g)/(1kg))	e
((337mg)/(1))times ((1000g)/(1mg))times ((1000kg)/(1g))

a brident finds that the muss of a chamcol sample is tident is meatend to report at muscrements in proper S I the student must convert the music to kilograms. What is echamical sample in kilograms? ((337mg)/(1))times ((1g)/(1000mg))times ((1kg)/(1000g)) e ((337mg)/(1))times ((1000mg)/(1g))times ((1g)/(1000kg)) e ((337mg)/(1))times ((1g)/(1000mg))times ((1000g)/(1kg)) e ((337mg)/(1))times ((1000g)/(1mg))times ((1000kg)/(1g))

Solución

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Rafaelprofessionell · Tutor durante 6 años
expert verifiedVerificación de expertos
4.7 (156 votos)

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To convert the chemical sample from milligrams (mg) to kilograms (kg), we need to use the appropriate conversion factors.<br /><br />The correct conversion factor is:<br />$(\frac {337mg}{1})\times (\frac {1g}{1000mg})\times (\frac {1kg}{1000g})$<br /><br />Let's break down the steps:<br />1. Convert milligrams (mg) to grams (g) using the conversion factor $(\frac {1g}{1000mg})$.<br />2. Convert grams (g) to kilograms (kg) using the conversion factor $(\frac {1kg}{1000g})$.<br /><br />Now, let's calculate the final result:<br />$(\frac {337mg}{1})\times (\frac {1g}{1000mg})\times (\frac {1kg}{1000g}) = 0.000337 kg$<br /><br />Therefore, the chemical sample is 0.000337 kilograms.
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