HsF8+4Cs2Searrow 8CsF+HsSe4 How many moles of HsSe4 do I get from 0.65 moles of HsF8 and 1.91 moles of Cs2Se 0.478 0.65 2.6 7.64

To determine how many moles of HsSe4 are produced from 0.65 moles of HsF8 and 1.91 moles of Cs2Se, we need to use the stoichiometry of the balanced chemical equation.<br /><br />The balanced chemical equation is:<br />$HsF8 + 4Cs2Se \rightarrow 8CsF + HsSe4$<br /><br />From the equation, we can see that 1 mole of HsF8 reacts with 4 moles of Cs2Se to produce 1 mole of HsSe4.<br /><br />Given that we have 0.65 moles of HsF8 and 1.91 moles of Cs2Se, we need to determine the limiting reactant.<br /><br />To do this, we can compare the mole ratio of HsF8 to Cs2Se:<br /><br />Mole ratio of HsF8 to Cs2Se = 0.65 moles / 1.91 moles = 0.34<br /><br />Since the mole ratio of HsF8 to Cs2Se is less than 1, HsF8 is the limiting reactant.<br /><br />Therefore, the number of moles of HsSe4 produced will be equal to the number of moles of HsF8, which is 0.65 moles.<br /><br />So, the correct answer is 0.65 moles of HsSe4.