Question 2 (2 points) How many moles of LiMnO_(4) are in 0.107 Lof 2 M solution? __ mol (Answer should contain 1 significant figure). Blank 1: square

To find the number of moles of $LiMnO_{4}$ in 0.107 L of a 2 M solution, we can use the formula:<br /><br />Number of moles = Molarity (M) × Volume (L)<br /><br />Given:<br />Molarity (M) = 2 M<br />Volume (L) = 0.107 L<br /><br />Substituting the values into the formula:<br /><br />Number of moles = 2 M × 0.107 L<br />Number of moles = 0.214 mol<br /><br />Therefore, the number of moles of $LiMnO_{4}$ in 0.107 L of a 2 M solution is 0.2 mol (rounded to 1 significant figure).