An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the right. What is the displacement of the object? 1 5 7 13

## Step 1<br />The problem involves the concept of displacement on a number line. Displacement is the overall change in position of an object, regardless of the path taken. In this case, the object starts at 0 on the number line.<br /><br />## Step 2<br />The object first moves 3 units to the right. This is a positive displacement, so we add 3 to the initial position of 0.<br /><br />## Step 3<br />Next, the object moves 4 units to the left. This is a negative displacement, so we subtract 4 from the current position.<br /><br />## Step 4<br />Finally, the object moves 6 units to the right. This is another positive displacement, so we add 6 to the current position.<br /><br />## Step 5<br />The final displacement of the object is the sum of these three displacements.<br /><br />### **The formula for displacement is:**<br />### \(Displacement = Initial\ Position + Right\ Displacement - Left\ Displacement + Final\ Right\ Displacement\)<br /><br />## Step 6<br />Substitute the given values into the formula:<br /><br />### \(Displacement = 0 + 3 - 4 + 6 = 5\)