Answer in units of mm. __ 002 (part 1 of 2) 10.0 points How much pressure is applied to the ground by a 109 kg man who is standing on square stilts that measure 0 .06 m on each edge? Answer in units of Pa. __ 003 (part 2 of 2)10.0 points What is this pressure in pounds per square inch? Answer in units of lb/in^2

To solve this problem, we need to calculate the pressure applied to the ground by the man standing on the stilts.<br /><br />Given information:<br />- Mass of the man: 109 kg<br />- Length of each stilt: 0.06 m<br /><br />Step 1: Calculate the total area of the stilts.<br />Total area = 2 × (length of each stilt)^2<br />Total area = 2 × (0.06 m)^2 = 0.0072 m^2<br /><br />Step 2: Calculate the pressure applied to the ground.<br />Pressure = Force / Area<br />Force = Mass × Acceleration due to gravity<br />Force = 109 kg × 9.8 m/s^2 = 1072.2 N<br />Pressure = 1072.2 N / 0.0072 m^2 = 14883.33 Pa<br /><br />Therefore, the pressure applied to the ground by the man standing on the stilts is 14883.33 Pa.<br /><br />To convert this pressure to pounds per square inch (lb/in^2), we need to use the conversion factor:<br />1 Pa = 0.000145038 lb/in^2<br /><br />Pressure in lb/in^2 = 14883.33 Pa × 0.000145038 lb/in^2 = 2.16 lb/in^2<br /><br />Therefore, the pressure applied to the ground by the man standing on the stilts is 2.16 lb/in^2.