What are the coordinates that best represents the vertex of the function x^2-16=6

To find the coordinates that best represent the vertex of the function $x^2 - 16 = 6$, we first need to rewrite the equation in the standard form of a quadratic function, which is $y = ax^2 + bx + c$.<br /><br />Given equation: $x^2 - 16 = 6$<br />Rearranging the equation, we get: $x^2 - 22 = 0$<br /><br />Comparing this with the standard form, we have:<br />$a = 1$, $b = 0$, and $c = -22$<br /><br />The vertex of a quadratic function in the form $y = ax^2 + bx + c$ is given by the formula:<br />$x = -\frac{b}{2a}$<br /><br />Substituting the values of $a$ and $b$, we get:<br />$x = -\frac{0}{2(1)} = 0$<br /><br />To find the y-coordinate of the vertex, we substitute the value of $x$ back into the original equation:<br />$y = 0^2 - 16 = -16$<br /><br />Therefore, the coordinates that best represent the vertex of the function $x^2 - 16 = 6$ are $(0, -16)$.