Problemas

13. Phosphorous reacts with bromine to create phosphorous bromide. When calculated, 523 g of PBr_(3) was supposed to be produced, but only 468 g were acquired.What is the percent yield? 68.3% 89.5% 26.7% 98.2%
Solución
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Yadiramaestro · Tutor durante 5 años
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To calculate the percent yield, we need to compare the actual yield (the amount of product obtained) with the theoretical yield (the amount of product that should have been obtained if the reaction had gone perfectly).<br /><br />Given information:<br />- Theoretical yield of $PBr_{3}$ = 523 g<br />- Actual yield of $PBr_{3}$ = 468 g<br /><br />Percent yield = (Actual yield / Theoretical yield) × 100<br /><br />Substituting the values, we get:<br /><br />Percent yield = (468 g / 523 g) × 100<br /> = 89.5%<br /><br />Therefore, the correct answer is $89.5\%$.
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