6. A 0.5 kg pineapple is hanging on a tree 10 m above the earth's surface when it begins to fall.If its velocity is 13m/s the second before it hits the ground how much energy was lost to air resistance? A) 6.8 J (Show Work Here)

To solve this problem, we need to calculate the potential energy of the pineapple when it was hanging on the tree, the kinetic energy of the pineapple just before it hits the ground, and then find the difference between these two values to determine the energy lost to air resistance.<br /><br />Given information:<br />- Mass of the pineapple (m) = 0.5 kg<br />- Height of the tree (h) = 10 m<br />- Velocity of the pineapple just before it hits the ground (v) = 13 m/s<br /><br />Step 1: Calculate the potential energy of the pineapple when it was hanging on the tree.<br />Potential energy (PE) = m × g × h<br />Where:<br />- m is the mass of the pineapple (0.5 kg)<br />- g is the acceleration due to gravity (approximately 9.8 m/s²)<br />- h is the height of the tree (10 m)<br /><br />PE = 0.5 kg × 9.8 m/s² × 10 m = 49 J<br /><br />Step 2: Calculate the kinetic energy of the pineapple just before it hits the ground.<br />Kinetic energy (KE) = 0.5 × m × v²<br />Where:<br />- m is the mass of the pineapple (0.5 kg)<br />- v is the velocity of the pineapple just before it hits the ground (13 m/s)<br /><br />KE = 0.5 × 0.5 kg × (13 m/s)² = 42.25 J<br /><br />Step 3: Calculate the energy lost to air resistance.<br />Energy lost to air resistance = Potential energy - Kinetic energy<br />Energy lost to air resistance = 49 J - 42.25 J = 6.75 J<br /><br />Therefore, the energy lost to air resistance is approximately 6.8 J.<br /><br />The correct answer is A) 6.8 J.