2. A L flask contains argon at 3.50 atm and 127^circ C How many moles of argon are present?

To find the number of moles of argon present in the flask, we can use the ideal gas law equation:<br /><br />PV = nRT<br /><br />Where:<br />P = Pressure (in atm)<br />V = Volume (in L)<br />n = Number of moles<br />R = Ideal gas constant (0.0821 L·atm/mol·K)<br />T = Temperature (in Kelvin)<br /><br />Given information:<br />- Pressure (P) = 3.50 atm<br />- Temperature (T) = 127°C = 400.15 K (converted to Kelvin)<br /><br />We need to find the number of moles (n).<br /><br />Rearranging the ideal gas law equation to solve for n:<br />n = (PV) / (RT)<br /><br />Substituting the given values:<br />n = (3.50 atm × 2.00 L) / (0.0821 L·atm/mol·K × 400.15 K)<br />n = 106.6 moles<br /><br />Therefore, there are 106.6 moles of argon present in the 2.00 L flask at 3.50 atm and 127°C.