Question 2 (2 points) 16Al+3S_(3)arrow 8Al_(2)S_(3) Given the above reaction match the following questions to the correct answer. Column A 1. square If 8 moles of aluminum react with an excess of sulfur, how many grams of product will form? 2 __ If 8 grams of aluminum react with an excess of sulfur, how many grams of product will form? 3. __ II 20g of aluminum react completely, how many moles of sulfur rescled? Column B a. 0.6 b. 0.1 C. 3 d. 600 e. 20

1. The molar mass of Al2S3 is 150.17 g/mol. According to the balanced chemical equation, 16 moles of Al react with 3 moles of S3 to produce 8 moles of Al2S3. Therefore, if 8 moles of Al react with an excess of S3, 8 moles of Al2S3 will be produced. The mass ofS3 produced is 8 moles * 150.17 g/mol = 1200.36 g, which is approximately 600 g. So, the answer is d. 600.<br />2. The molar mass of Al is 26.98 g/mol. Therefore, 8 g of Al is approximately 0.3 moles. According to the balanced chemical equation, 16 moles of Al react with moles of S3 to produce 8 moles of Al2S3. Therefore, 0.3 moles of Al will produce 0.3/2 = 0.15 moles of Al2S3. The mass of Al2S3 produced is 0.15 moles * 150.17 g/mol = 22.52 g, which is approximately 20 g. So, the answer is e. 20.<br />3. The molar mass of Al is 26.98 g/mol. Therefore, 20 g of Al is approximately 0.74 moles. According to the balanced chemical equation, 16 moles of Al react with 3 moles of S3. Therefore, 0.74 moles of Al will react with 0.74/16 * 3 = 0.14 moles of S3. So, the answer is b. 0.1.