nvestigation 7 Test -L Balance the following equation: square C_(5)H_(12)+square O_(2)arrow square H_(2)O+square CO_(2)

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $C_{5}H_{12} + O_{2} \rightarrow H_{2}O + CO_{2}$<br /><br />Step 1: Balance the carbon atoms.<br />There are 5 carbon atoms in $C_{5}H_{12}$, so we need 5 $CO_{2}$ molecules on the product side to balance the carbon atoms.<br /><br />$C_{5}H_{12} + O_{2} \rightarrow H_{2}O + 5CO_{2}$<br /><br />Step 2: Balance the hydrogen atoms.<br />There are 12 hydrogen atoms in $C_{5}H_{12}$, so we need 6 $H_{2}O$ molecules on the product side to balance the hydrogen atoms.<br /><br />$C_{5}H_{12} + O_{2} \rightarrow 6H_{2}O + 5CO_{2}$<br /><br />Step 3: Balance the oxygen atoms.<br />Now, let's count the oxygen atoms on the product side. We have 6 oxygen atoms from 6 $H_{2}O$ and 10 oxygen atoms from 5 $CO_{2}$. In total, we have 16 oxygen atoms on the product side.<br /><br />To balance the oxygen atoms, we need 8 $O_{2}$ molecules on the reactant side.<br /><br />$C_{5}H_{12} + 8O_{2} \rightarrow 6H_{2}O + 5CO_{2}$<br /><br />Therefore, the balanced chemical equation is:<br />$C_{5}H_{12} + 8O_{2} \rightarrow 6H_{2}O + 5CO_{2}$